Voltaic Cell Concept Review For the following shorthand notations Write out the
ID: 559440 • Letter: V
Question
Voltaic Cell Concept Review For the following shorthand notations Write out the balanced redox reaction ·Calculate the standard cell potential (E Determine if the reaction is voltaic or electrolytic a. Zn(s) | Zn2 (aq) lI Ag (aq) | Ag(s) b. Cu(s) | Cu2*(aq) ll Sn2 (aq) | Sn(s) c. Pb(s) | Pb2*(aq) II OH-(aq) | O2(9) | Pt(s) 3. a. If you want to plate gold, would the following half-reaction need to be the cathode or the E' = +1.50 V anode? Au3+(aq) + 3e- Au(s) Which of the following half-reactions could be paired with the gold reaction above to make a voltaic cell that would plate gold? b. F2(g) + 2e- 2F-(aq) 12(s) + 2e- 2I-(aq) E' = +2.87 V E' = +0.53 V C. Write out the balanced voltaic reaction and calculate the cell potential, EExplanation / Answer
2.
a) ( Zn --------------- Zn+2 + 2e- ) X 1
+ ( Ag+ + e- ------------- Ag ) X 2
-----------------------------------------------
Zn + 2 Ag+-------------------- Zn+2 + 2 Ag ~~~ balanced redox reaction
E` oxidation of Zn =+0.76
E` reduction of Ag+= +0.80
Hence E` cell = E` oxidation of Zn + E` reduction of Ag+
E` cell = +0.76 + (+0.80)
= +1.56 V
It is a Voltaic cell.
b) . Cu --------------- Cu +2 + 2e-
+ Sn+2 + 2e- --------------- Sn
--------------------------------------------
Cu + Sn+2 ------------ Cu +2 + Sn ~~~ balanced redox reaction
E` oxidation of Cu = -0.34
E` reduction of Sn+2 = -0.14
Hence E` cell = E` oxidation of Cu + E` reduction of Sn+2
E` cell = -0.34 + (-0.14)
= - 0.48 V
It is a electrolytic cell.
c). ( Pb ----------------- Pb+2 + 2e-) X 2
+ ( OH- ---------------------- O2 + 4e- + 2 H20 ) x 1
--------------------------------------------------------------------------
2Pb + OH- ---------------------- 2 Pb+2 + O2 + 2 H20 `~~~~~ balanced redox reaction
E` oxidation of Pb = +0.13
E` reduction of OH- = -0.40
Hence E` cell = E` oxidation of Pb + E` reduction of OH -
E` cell = +0.13 + (-0.40)
= - 0.27 V
It is a electrolytic cell.
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