For a reaction that has a positive value of H and a negative value of S, which s
ID: 559249 • Letter: F
Question
For a reaction that has a positive value of H and a negative value of S, which statement is true at equilibrium?
a) Reactants are favored at very low temperatures and reactants are favored at very high T
b) Reactants are favored at very low temperatures and products are favored at very high T
c) Products are favored at very low temperatures and reactants are favored at very high T
d) Products are favored at very low temperatures and products are favored at very high T
Note: “Reactants are favored” means they are present at equilibrium in greater amounts than products.
Explanation / Answer
option a
When delta H is positive it is endo thermic reaction , not favorable for formation of products.
delta S is also negative which is again not favorable for product formation.
We know
delta G = delta H - T.delta S
for a reaction to be spontaneous (favorbale in the given direction) delta S has to be negative.
However the givendelta H positive and delta S negative can never give a negative value for Delta G (at low or high temperatures).
Thus the reaction remains non-spontaneous at all temperatures, which means it is reactant favored at all temperatures.
Thus option a
reactants are favored at very low temperatures and reactants are favord at very high temperature is correct.
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