15) The reaction 2 Os (3) -302 (g) is second order in Os, and the order with res

Question

15) The reaction 2 Os (3) -302 (g) is second order in Os, and the order with respect to O2 is The found to be -1 rate constant is 26x IgA s-1 at a certain temperature. what is the rate of the reaction if lol 021-3.4 10-2 M 10-3 M and A) 0.93 26-104 B) 0.97 C) 1.1 10-3 D) 840 16) The rate constant for a particular reaction is 2.7 10-2s-1 at 25 C and 62 1051 at 115Cwhat is the , activation energy for the reaction, in kJ/mol? A) 87 B) 13 C) 0.089 D) 0.0045 17) The activation energy for a reaction is 37.6 kJ/mol. The rate constant for the reaction is Calculate the rate constant at 145°C A) 0.38 B) 0.56 C) 8.4 10- D) 5.5 103 E) 0.16 18) For the reaction A -B, the activation energy, Ea-125 kJ/mol and the heat of reaction, H-50 kJimol, what is the Ea for the reverse reaction, in kJ/mol? A) 125 B) 175 C)-175 D) 75 E) -75 19) Consider the following 2-step mechanism. Which of the species in the mechanism is the catalyst? fast step H202 o -H20 02sw step 2H202-2 H20 0 net reaction A) H20 B) 02 C) H202 D) ol 20) If the activation energy for the forward reaction is greater than the activation energy for the reverse reaction, the reaction is A) faster in the reverse direction exothermic faster in the forward direction.

Explanation / Answer

15)

Rate law as per question is:

rate = k [O3]^2 [O2]^-1

= (2.6*10^4 )*(1.1*10^-3)^2*(3.4*10^-2)^-1

= (2.6*10^4 )*(1.1*10^-3)^2 / (3.4*10^-2)

= 0.93

Answer: a

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