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Kean University-CHEM 1084-F 4Jump to.. Jessic CHEM 1084-Falli7-DOSS Activities a

ID: 558740 • Letter: K

Question

Kean University-CHEM 1084-F 4Jump to.. Jessic CHEM 1084-Falli7-DOSS Activities and Due Dates Required HW 20 11/12/2017 11:55 PM O 8.1/2011/12/201712:23 AM Grad Print Caloulalor Periodic Table Question 17 of0 Mapd Sapling Learning The equilibrium constant, K, for a neutralization reaction can be symbolized as Kn Using K and the K, and K, values from these tables, determine K, for the following reaction at 25 C. Number OPruvous Gve Up S View Solton eCheck Answer ONed eEn about is carees privacy pocy teins of use cotact us ep

Explanation / Answer

NH3(aq)+ HBrO(aq) <--> NH+4 (aq) + BrO- (aq) Kn= {[NH4+]*[ BrO-]}/{[NH3]*[HBrO]}

(A) NH3 + H2O < ---> NH4+(aq) + OH-(aq) Kb = {[NH4+]*[OH-]}/{NH3] = 5.8 x 10-10

(B)  HBrO(aq) <--> H+ + BrO- Ka = [H+ ] [BrO- ] / [HBrO] = 2x10-9

Kn = Ka*Kb / Kw

= ( 2x10-9 x 5.8 x 10-10 )/ 1x10-14

= 1.16 x 10-5