The human body obtains 1086 kJ from a candy bar. Part A If this energy were used
ID: 558538 • Letter: T
Question
The human body obtains 1086 kJ from a candy bar. Part A If this energy were used to vaporize water at 100 C, how much water in liters could be vaporized? (Assume that the density of water is 1.0 g/mL.) The heat of vaporization of water at 100 C is 40.7 kJ/mole. ..1 Verizon LTE 4:59 PM a session.masteringchemistry.com C Exercise 12.54 Mastering Chemistry 5 of 10 Exercise 12.54 The human body obtains 1086 k.J from a candy bar. Part A If this energy were used to vaporize water at 100 °C, how much water in liters could be vaporized? (Assume that the density of water is 1.0 g/mL.) The heat of vaporization of water at 100 C is 40.7 kJ/mole. Express your answer using two significant figures. Submit Give Up Continue >Explanation / Answer
Heat supplied(q) = dHvap*n
1086 = 40.7*n
n = no of mol of water = 26.68 mol
mass of water = n*M
= 26.68*18
= 480.24 grams
volume of water = mass/density = 480.24/1 = 480.24 ml
= 0.48 L
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.