ake home group-based project due to Founder\'s Day and Honors Convocation (due o

Question

ake home group-based project due to Founder's Day and Honors Convocation (due on Monday 3/2s) Each group is to turn in one hard copy answers with all members' names Circle the answer and Must show detail steps in spearate sheet Names MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) In the reaction, A - Products, the initial concentration of A is 1.60 M, and 45 s later it is 1.20 M. What is the initial rate of this reaction in M s-1? 10-2 A) 3.5 10-2 B) 2.7 C)8.9 10-3 D) 3.1 10-2 E) 8.0 10-3 2) In the reaction, A - Products, the initial rate of reaction is 3.6 10-4M -1 when the initial concentration of A is 0.583 M. What will [A]be at t- 25 s? A) 0.462 B) 0.146 C) 0.009 D) 0.574 E) 0.344 3) Which of the following statements would be correct regarding the following reaction? 2H2 (g) + g)-2H2O(g) A) The rate of H20 appearance is equal to the rate of 02 disappearance. B) The rate of H2 disappearance is twice the rate of O2 disappearance. C) The rate of H2 disappearance is equal to the rate of O2 disappearance D) The rate of O2 disappearance is twice the rate of H2 disappearance. E) The rate of H20 disappearance is twice the rate of O2 disappearance. he follorwing time and concentration data s obtained for the reaction: 2 A Products t (min)I [Al 0 1.20 1.1 1.00 2.3 0.80 4.0 0.60 5.1 0.50 6.3 0.40 8.0 0.30 10.3 |0.20 Figure 13.2 min-1, E) 0.11 4) Refer to Figure 13.2 and, without drawing a graph, estimate the initial rate of the reaction, in M A) 1.1 B) 0.097 C) 0.83 D) 0.18 5) In the reaction A +3B-C+2D, the rate of reaction of A is found to be 1.5 10-1 M 1. What is the rate of reaction of B? A) 1.5× 10-1 B)30 x 10-1 C) 6.0 x 10-1 ) 5.0 x 10-2 E) 4.5 x 10-1

Explanation / Answer

Ans 1 : c) 8.9 x 10-3

The initial concentration of A = 1.60 M

The final concentration of A = 1.20 M

So the change in concentration of A = 1.60 - 1.20

= 0.40 M

The rate of reaction = change of concentration / time in s

= 0.40 / 45

= 8.9 x 10-3 M /s

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