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eme a chemistry i 100 M6A1/M6BLM6CL-Lecture Test #2-1 asan s I. A sample of air

ID: 557958 • Letter: E

Question

eme a chemistry i 100 M6A1/M6BLM6CL-Lecture Test #2-1 asan s I. A sample of air at 298 K and 0910 atm contains 0.0698 mol of N,(g) and 0.0232 mol of O in the sample. (This problem can be solved with or without knowing the temperature.) igible amounts of carbon dioxide, water vapor, and other gases). Compute the and 0.0232 mol of O,(8) (plus O,(8) and Optr partial pressures of Answer: P,,-0.683 atm Po -0.226 -atm 14. Decomposition of hydrazine (N,H) was studied in an expandable vessel under constant pressure of 1.00 atn at25.0 N2H4 (l) N2 (g) + 2 H2(g) Determine the total volume of the gas products generated by the decomposition of 1.65 g of hydrazine. The molecular weight of hydrazine is 32.0 amu. 8pts Answer: Total volume of gases .379

Explanation / Answer

Q13

x-O2 = mol of O2 / Total mol = 0.0232/(0.0232+0.0698) = 0.2494

x-N2 = mol of N2 / Total mol  = 0.0698/(0.0232+0.0698) = 0.75053

Partial Pressure

P-O2 = x-O2 * Ptotal = 0.2494*0.91 = 0.226954 atm

P-N2 = x-N2 * Ptotal = 0.75053*0.91 = 0.6829 atm

Q14.

mol of hydrazine = mass/MW = 1.65/32 = 0.05156

then..

1 mol of hydrazine = 1+2 = 3 mol of gases

0.05156 mol --> 3*0.05156 = 0.15468

At

PV = nRT

V = nRT/P = (0.15468)(0.082)(298)/1

V = 3.7797L