2Pe(s) + O2(g) + 2H20(1) 2Fe(OH),(s) 4Fe(OH),() +02(8) +2H,00)+4Fe(OH)(6) Part C

Question

2Pe(s) + O2(g) + 2H20(1) 2Fe(OH),(s) 4Fe(OH),() +02(8) +2H,00)+4Fe(OH)(6) Part C One way to reverse the chemical reaction and tun silver suffide back into siver is by immersing the silver in an aluminum container Sted with a hot solution of sodium bicarbonate Metals lke aluminum have a greater affei for sullur than silver This tamish-removal method uses a chemical reaction to convert the silver sulfide back into silver, resulting in no net loss of silver. The reaction between slver sulfide and aluminum takes place in the presence of a sodium bicarbonate (NalCO,) soluion, resulting in the transfer of sufur atoms from siver to aluminum, freeing the silver metal and forming aluminum sufide The reaction can be summarized as follows: when silver sultfide reacts with aluminum, silver sulfide is reduced to form siver and aluminum is axidiced to form aluminum sulide Completelhe balancedchemical equation for tho reactor, showingthe formaion of siver met tom sher slfoeinthe presence of annum metal Express your answer as the products of a chemical equation Hints 7 8 9 4 5

Explanation / Answer

answer : 6 Ag   +   Al2S3

Explanation :

balanced chemical equaiton :

3 Ag2S   + 2 Al   ------------> 6 Ag   + Al2S3

here Ag2S and Al reacts and form Ag (silver) and Al2S3

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.