what initial volume does the air occupy at atmospheric pressure and at a tempera
ID: 557447 • Letter: W
Question
what initial volume does the air occupy at atmospheric pressure and at a temperature of 5. (1s points) When filling a hot air balleon the air inside tle bohe alr spands eated from expands 20C to 93C at constant atmospliericsure balloon at MC When from its initial volume at 20 C to fill t completely inflated, the balloon has a volume of 2,800 m Since the volume that the air occupies has increased (while the mass of the air stays the same), the density ot the air inside the balloon is less than the density of the surrounding air which causes the balloon to float. The specific heat of airis 1003.Js C atm> The h a. What initial volume (in L) does the air occupy at atmospheric pressure (1.00 atm) and at a temperature of 20°C7 b. What is the mass of the air in the balloon? The density of air at 20°C is 1.204 kg/m C. Calculate g, w, E, and H for this processExplanation / Answer
As the process is at constant pressure we can use V1/T1=V2/T2
V1/293K = 2800/372K. (To convert degree celsius to kelvin we are adding 273)
So V1= 2800*293/372= 2205 M3= 2.205 x 10^6 Litres
Mass= density x volume = 2205 x 1.204= 2654.82Kg
Heat energy supplied to inflate = mass x specific heat x temperature change
2654.82Kg x 1003 J/Kg x79= 2.166 x 10^8 Joules or 2.166 x 10^5 KJ
Work done during expansion = pressure x volume change = 1 x10^5 Pascalx (2800-2205)M3
= 595 x 10^5 Joules or 0.595 x 10^5 KJ
Internal energy change = q-w= (2.166-0.595)x10^5= 1.571 x10^5 kJ
Enthalpy change = Internal energy change + work done during expansion
1.571x10^5+0.595x10^5= 2.166x10^5 kJ which is nothing but heat absorbed during the reaction
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