a) Balance the following equation. NaBH4 +I2 ->. B2H6+ NaI+ H2 b) Calculate the

Question

a) Balance the following equation. NaBH4 +I2 ->. B2H6+ NaI+ H2 b) Calculate the theoretical mass of B2H6 possible from the reaction of 10.5 g of NaBH4. c) Suppose the reaction yields 3.24 g of B2H6. What is the percentage of yield? a) Balance the following equation. NaBH4 +I2 ->. B2H6+ NaI+ H2 b) Calculate the theoretical mass of B2H6 possible from the reaction of 10.5 g of NaBH4. c) Suppose the reaction yields 3.24 g of B2H6. What is the percentage of yield? a) Balance the following equation. NaBH4 +I2 ->. B2H6+ NaI+ H2 b) Calculate the theoretical mass of B2H6 possible from the reaction of 10.5 g of NaBH4. c) Suppose the reaction yields 3.24 g of B2H6. What is the percentage of yield?

Explanation / Answer

Ans (a) Balanced chemical equation:-

2NaBH4 + I2 = B2H6 + 2NaI + H2(g)

Ans (b) 2 * 37.83 g of NaBH4 gives 27.66 g of B2H6

10.5g of NaBH4 gives (27.66 * 10.5 / 75.66) = 3.838 g of B2H6 formed

Ans (c) observed yield = 3.24 g

% yield = observed yield * 100 / theoretical yield = 3.24 * 100 / 3.838 = 84.4%

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.