2. For each trial with the unknown acid, calculate the following Trial 2: Moles

Question

2. For each trial with the unknown acid, calculate the following Trial 2: Moles of NaOH required to reach the equivalence point Moles of unknown acid in the beaker Molar mass of unknown acid Trial 3 Moles of NaOH required to reach the equivalence point Moles of unknown acid in the beaker Molar mass of unknown acid Titration of Unknown acid Trial #1 Ma Initial Volume of NaOH in burette 9.9 Volume of NaOH in burette at Titration of Unknown acid Trial #2 231 Mass of Initial Volume of NaOH in burette 3.27 Volume of NaOH in burette at 9.75 Titration of Unknown acid Trial #3 Value Mass of 249 Initial Volu in burette 3.27 23.9 9.57 Volume of NaOH in burette at An #1 Value 246 Correct Concentration of NaOH from trial #1 Correct Concentration of NaOH from trial # Average Concentration of NaOH Solution is #2 Trial #2 Value Moles of NaOH required at in be Molar mass of unknwon Analysis #2 . Trial #3 Moles of NaOH required at Moles of unknown acid present in be Molar mass of unknwon

Explanation / Answer

Determination of molar mass of unknown acid

Trial#2

Volume of NaOH to reach equivalence point = 11.0 ml

moles of NaOH to reach equivalence point = 0.24 M x 11.0 ml/1000 = 0.00264 mol

moles of acid present in solution = 0.00264 mol

molar mass of the unknown acid = 0.231 g/0.00264 mol = 87.50 g/mol

Trial#3

Volume of NaOH to reach equivalence point = (23.9 - 11) = 12.9 ml

moles of NaOH to reach equivalence point = 0.24 M x 12.9 ml/1000 = 0.0031 mol

moles of acid present in solution = 0.0031 mol

molar mass of the unknown acid = 0.249 g/0.0031 mol = 80.32 g/mol

Formulas used,

molarity = moles/L of solution

moles = grams of solute/molar mass of solute

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