t is Dalton\'s I 1023 molecules. It is a law that states that a volume of 22.4 L
ID: 556006 • Letter: T
Question
t is Dalton's I 1023 molecules. It is a law that states that a volume of 22.4 L PTotal Pi+ P2 + P3+ 13) QID: 5844 At STP (standard temperature and pressure), there are 0.0357 moles of methane gas (CH4 ) in an 8.0 × 10-mL cylinder. What is the pressure exerted by the gas in the cylinder if the temperature is raised from 273 K to 320 K?.u7 atm 0.938 atm 1.2 atm 0.172 atm n,0357 CH 14) QID: 26370 0.0 mL of a sulfuric acid solution of unknown molarity is 0.25 M H2SO4 titrated against 27.3 mL of a standardized 0.55 M sodiunm hydroxide solution. What is the concentration of the sulfuric 0.50 M H2SO4 0.45 M H2SO4 0.75 M H2SO4 acid solution? Recall that sulfuric acid is a diprotic acid. 15) QID: 26381 A 15.00 mL sample of unknown concentration of sulfuric acid is precititated with excess lead(II) nitrate and a precipitate of lead(II) sulfate is collected. The dried sample of PbSO4 has a mass of 5.354 grams. What is the concentration of the unknown sulfuric acid solution? 0.8510 M 1.175 M 0.3500 M 0.5700 M http://my.thinkwell.com/twtest/printrandom.cfm
Explanation / Answer
Q1
STP = 1 atm , T = 273 K
P1V1/T1n1 = P2V2/T2n2
1*(800)/(273 * 0.0357) = P2*800 /(320 * 0.0357)
P2 = 1*320/273 = 1.17 atm
P new = 1.20 atm
Q14.
mmol of NAOH = MV = 0.55*27.3 = 15.015
mmol o H2SO4 = 1/2*mmol of base = 15.015/2 = 7.5075
[H2SO4] = mmol/V = 7.5075/30 = 0.25025 M
Q15
mol of PbSO4 = mass/MW = 5.354/303.26 = 0.017654
[SO4-2] = [PbSO4] = 0.017654 / (15*10^-3) = 1.17693M
choose 1.175 M
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