onto Toin ted ai eding resource trom Cengage Learning takeCovalentActivity.do?lo
ID: 555813 • Letter: O
Question
onto Toin ted ai eding resource trom Cengage Learning takeCovalentActivity.do?locator assignment-take&takeAssignmentSessionL.ocator-assignment-take; Use the References to access important values if needed for this question ion concentration in a solution may be determined by the precipitation of lead bromide Pb()+2Br(aq)PbBr2s) A student finds that 19.97 mL of 0.7580 M lead nitrate is needed to precipitate all of the bromide ion in a 10.00-mL sample of an unknown. What is the molarity of the bromide ion in the student's unknown? Submit Answer Retry Entire Group 8 more group attempts remaining F4 FS FS F8 F9 F1OExplanation / Answer
a)
mmol of Pb+2 = mmol of Pb(NO3)2
mmol of Pb(NO3)2 = MV = (0.758*19.97) = 15.13726
then
we need
2 mmol of Br = 1 mmol fo Pb
15.13726 mmol of Pb = 2*15.13726
mmol of Br- = 30.27452
[Br-] = mmol/V = 30.27452/10 = 3.027 M
[Br-] = 3.027 M
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