Part H Determine the possible combinations of multiple bonds and rings required

Question

Part H Determine the possible combinations of multiple bonds and rings required for Cs H4FN molecular formula. Check all that apply. There could be two double bonds and two rings There could be one triple bond and two rings. There could be two triple bonds and no rings. There could be two double bonds and three rings. There could be one double bond, two triple bonds and no rings. There could be two double bonds, two triple bonds and no rings. The molecule has no rings and no multiple bonds. Submit My Answers Give Up

Explanation / Answer

DBE = C+1-[(H+X-N)/2]

Here, C is carbon, H is hydrogen, X is halogen and N is nitrogen.

Molecular formula is C5H4FN.

So,
DBE = 5+1-[(4+1-1)/2]

         =4

Thus, one Benzene ring is present in the compound (1 pi bond consumed in the formation of the ring and the other 3 are present in the benzene ring).

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