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better view of calculation questions

Show the calculations for the determinations of the specitic heat capacity and the atomic weight and report the values in the table helow Calculations: Data table: Sample Mctal 1 Sample Metal 2 Sample Metal 3 Mass of the Metal Sample (g) Sample Mctal2 Sample Metal 3 Sample Metal ! b .152 ,09 40,3551 |44.05% | 46.6259 5%,366 |341, 303, 1394,2 602n, 302, Ls y Mass of the empty Insulating Cup (g) 3, 09l Specific Heat of the Sample (cal/g) Mass of the Cold Water and Atomic weight of the metal Mass of the Cold Water (g) Initial Temperature of the Cold Water Explain in your own words the possible sources of errors in the experiments specitic heat and atomic weight of the different metals. Questions: 1) Initial Temperature of the Metal Sample (C) Intial Temperature-of the Cold Water quilibrium Temperature of the 2) If an unknown metal is given to you. Describe how you can determine its identity even if you are not given its specific heat capacity or it atomic weight

Explanation / Answer

Specific heat of metal

Sample metal 1 : In the first case no change in temperature of the cold water was seen by addition of the metal.

the expeirment needs to be repeated to get a correct final temperature.

Sample metal 3 : specific heat of metal = 303.65 g x 4.184 J/g.oC (24 - 23)/2.091 (97-24)

                                                               = 8.323

he specific heat is too high and it does not match any metal sample in the literature.

1) The experiment done here gives us incorrect values for the specific heat. The specific heat obtained are very high. The possible sources of error whch results in this discrepancy would be, incorrect measurement of initial and final equilibrium temperature of the solutions.

2) If an unknown metal is given, steps in determination of identity of metal

1. weight out cold water and metal

2. add metal to boiling water and let it come to that temperature

3. Now take the hot metal and put it in cold water. Note down the equilibrium temperature

4. The final temperature would be somewhere between room temperature and hot metal temperature.

5. heat of water is calculated as = weight of water x specific heat of water x (final temperature - cold water temperature)

6. heat lost by hot metal = heat hgained by cold water

heat lost by metal = mass of metal x specific heat of metal (unknown) x change in temperature of metal

specific heat of metal thus can be calculated for the metal and it can be compared with literature values to determine the dientity of the metal.

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