The de Broglie Relation and the Wavelength of a Particle Part A The mass of an e

Question

The de Broglie Relation and the Wavelength of a Particle Part A The mass of an electron is 9.11 × 10-31 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31 × 10-10 m, how fast is the electron moving relative to the speed of light? The speed of light is 3.00 × 108 m/s Just as light waves have particle behavior, a moving particle has a wave particle is moving, the higher its kinetic energy and the shorter its wavelength. The wavelength, , of a particle of mass m, and moving at velocity v, is given by the de Broglie relation nature. The faster the Express your answer numerically as a percent. Hints 0.732 % Submit mU 6.626 × 10-34 J·s is Planck's where h constant. My Answers Give Up This formula applies to all objects, regardless of size, but the de Broglie wavelength of macro objects is miniscule compared to their size, so we cannot observe their wave properties. In contrast, the wave properties of subatomic particles can be seen in such experiments as diffraction of electrons by a metal crystal Correct Part B The mass of a golf ball is 45.9 g . If it leaves the tee with a speed of 60.0 m/s , what is its corresponding wavelength? Express your answer with the appropriate units. Hints 2.26.10 34 m Submit My Answers Give Up

Explanation / Answer

so, we have:

v = 60 m/s

mass, m = 45.9 g

= 4.59*10^-2 kg [using conversion 1 Kg = 1000 g]

we have below equation to be used:

wavelength = Planck constant / (mass*velocity)

wavelength = (6.626*10^-34) / (4.59*10^-2*60)

wavelength = 2.41*10^-34 m

Answer: 2.41*10^-34 m

Feel free to comment below if you have any doubts or if this answer do not work

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