a. Define the degree of dissociation as a-6 na where 2 is the number of moles of

Question

a. Define the degree of dissociation as a-6 na where 2 is the number of moles of Cl g) present at equilibrium and n represents the number of moles of C g that would be present in the system if no dissociation occurred. Derive an expression for Kp in terms of no, , and P b. Derive an expression for as a function of K, and P olution a. We set up the following table Cl.(g) 2CI(g) Initial number of moles Moles present at equilibrium 25 Mole fraction present at equi brium, x, ()- Partial pressure at equilibrium, P,-x,P We next express Kn terms of no. , and P. #1 This expression is converted into one in terms of a: a P #2

Explanation / Answer

The electrons come initially from the solution. The I- donates itselectrons to become neutral and these electrons are

accepted by Cl, which becomes an anionic species(Cl-).

Yes, these electrons have to be equal in both the oxodisingand reducing half-cells, since electrons cannot be present inthe

solution for a long time, otherwise the cell reaction will notproceed forward(in accordance with Le-Chatliers principle. The electronsgiven by the relatively electropositive I- have to be accpetedby

the electronegative Cl completely, for the cell tofunction.

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