8) It was found that a new substance extracted from a tree in Neverland, compoun

Question

8) It was found that a new substance extracted from a tree in Neverland, compound K, had (2pts) strong antibacterial activity against staphylococcus aureus. It was found that a 2.500 g dried sample of the tree contained 1.153g compound K and the rest was other biochemical material such as carbohydrates, fats, and other inactive compounds. The compound K was crudely purified by a liquid-liquid extraction method developed by Dr. Lee and further purified by a recrystallization method developed by Dr. Shelby. You perform the extraction and recrystallization from 365.0 g of dried sample and recover 105.0 g of compound K. Calculate the percent recovery from the total compound K present 62% 46% 25% 29% O None of the above 9) Drs. Lee and Shelby found discovered a new organic compound (DBL SS 10 5 2014 4B; [a20- -15.1; n20 1.379.) from a guava tree, which displays an ability to reduce heart worms in dogs. You attempt to extract (DBL SS 10 5 2014B) from a guava tree, but until you do the GC-MS and NMR to confirm this, you obtain the following data in the meantime [al20--15.5; n20 -1.375. What does the refractive index tell you about your compound? (select all the best answers) (Select 212pts) The refractive index could be different because the room was colder than when Drs. Lee and Shelby ran their samples Potentially identifies a your extract as DBL-SS-10-5-2014-4B if there are a list of all compounds in the sample The refractive index of your extract indicates it may be impure DBL SS 10 5, 2014 4B or a different compound Positively identifies your extract as DBL-SS-10-5-2014-48 from any molecule ever O The refractive index of the extract positively excludes DBL SS.10 5 2014.4B

Explanation / Answer

Amount of compound K actually present in the dried sample=1.153g/2.5g

So amount present in 365.0g of dried sample=365.0g*(1.153g/2.5g)=168.338 g

% recovered=(amount recovered /actual amount present)*100=(105.0g/168.3338)*100=62.4%

Thus % recovery =62%

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