For each of the salts on the left, match the salts on the right that can be comp

Question

For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.

(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)

Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.

silver carbonate

copper(II) sulfide

Ksp =

Ksp =

Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

***** 1 & 2 COULD HAVE MORE THAN 1 ANSWER*****

Explanation / Answer

Solubility of AB, A2B, AB2, A3B, AB3, A2B3, A3B2

For solubility comparisson:

AB <-> A+ + B-; Ksp = [A+][B-] = S*S = S^2 --> S = sqrt(Ksp)

A2B <--> 2A+ + B-2 Ksp = [A+]^2[B-2] = (2S)^2 * S = 4*S^3 --> S = (Ksp/4)^(1/3)

AB2 <--> A+2 + 2B- ; Ksp = [A+2][B-]^2 = S* (2S)^2 = 4*S^3 --> S = (Ksp/4)^(1/3)

A3B <---> 3A+ + B-3 ; Ksp = [A+]^3[B-3] = (3S)^3 * S = 27*S^4 --> S = (Ksp/27)^(1/4)

AB3 <--> A+3 + 3B- ; Ksp = [A+3][B-]^3 = S* (3S)^3 = 27*S^4 --> S = (Ksp/27)^(1/4)

A3B2 <-->3A+2 + 2B-3; Ksp = [A+2]^3[B-3]^2 = (3S)^3 * (2S)^2 = 108*S^5 --> S = (Ksp/108)^(1/5)

A2B3 <-->2A+3 + 3B-2; Ksp = [A+3]^2[B-2]^3 = (2S)^2 * (3S)^3 = 108*S^5 --> S = (Ksp/108)^(1/5)

PbCl2 = AB2; Mn(OH)2 = AB2; AgCN = AB; Cu(OH)2 = AB2

Silver cabronate = Ag2CO3 --> A2B type salt,

then, A2B salts can be compared only with A2B and AB2 salts, which are:

PbCl2 = AB2; Mn(OH)2 = AB2; Cu(OH)2 = AB2

Now, for

Copper (II) Sulfide = CuS, this is type AB

then, only

PbCl2 = AB2; Mn(OH)2 = AB2; AgCN = AB; Cu(OH)2 = AB2

AgCN will do

Q2

for

Ag2CO3

Ksp = [Ag+]^2[CO3-2]

and for

CuS ---> Cu2+ + S2-

Ksp = [Cu2+][S2-]

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