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or 7. What is the significance of the compression factor z 7 The variation of \"

ID: 553340 • Letter: O

Question

or 7. What is the significance of the compression factor z 7 The variation of "Z" with pressure and temperature has been studied for different gases like hydrogen, these studies reveal about the behaviour of molecules in a methane and ammonia. What do (8 points) gas? 8. Calculate the difference in pressure of 10,00 g of carbon dioxide.confined to a container of 100 cm) at 25.0 ween treati 9. A sample of gas of volume of 0.55 dm2 at a pressure of 1,03 bar is compressed isothermally at by0.57% y beingsubjectedtoacostantexterralpressureof 952 bancalculate the work involved this 207 10. Determine the work done when 10.0 mol of propane gas molecules react with o produce carbon dioxidg and lauild watr at 25 CH 5 Oig -3 COM 4HOD 11. What is the energy needed to raise the temperature of a sample of 125 g of water by 40 C? 12. What is the heat capacity of a sample of liquid that rose in temperature by 5.23 0C when an energy of 124 Joules is supplied as heat?

Explanation / Answer

Answer: 7)

As we know that,

Compression factor (Z) = molar volume of a gas/ molar volume of an ideal gas

value of Z varies from 0 to 1

significances-

compression factor define the behavior of a gas

a) if Z = 1 i.e. ideal gas behavior

b) if Z < 1 that means a molar volume of gas, not greater then a molar volume of an ideal gas, attractive forces dominate in gas molecules and molecules are moving freely

c) Z > 1 that means a molar volume of a gas is greater than a molar volume of an ideal gas, repulsive forces dominate in gas molecules.

=> It reveals that any pure gas at the same reduced temperature, and reduced pressure, should have the same compression factor.

answer 11)

given that

mass of sample (h2o) = 125g and raise the temperature from 25 to 40 degree.

we know that,

specific heat of water (c) = 4.18 J/g.degree and

the heat absorbed by sample (q) = m*c*deltaT

m = 125g = mass of sample

So, q = 125 * 4.18 * (40 -25) (where 25 = initial temperature)

q = 7.837KJ

if initial temperature = 0 degree

then q = 25*4.18*40

q = 20.9KJ