In the laboratory you are given the task of separating ba2+ and pb2+ ions in an

Question

In the laboratory you are given the task of separating ba2+ and pb2+ ions in an aqueous solution. In the laboratory you are given the task of separating Ba2+ and Pb2+ ions in aqueous solution. For each reagent listed below indicate if it can be used to separate the ions. Type "Y" for yes or "N" for no. If the reagent CAN be used to separate the ions, give the formula of the precipitate. If it cannot, type "No" YorN Reagent Formula of Precipitate if YES KBr Na CO3 Na2S Submit Answer Retry Entire Group 1 more group attempt remaining

Explanation / Answer

If KBr --> K+ + Br- is present

then

Ba+2 will NOT form preciptiate, and PB2+ + 2Br- = PbBr2(s) will form

then, this is "YES"

b)

if Na2CO3 is added, then 2Na+ + CO3-2 is added, this becomes basic media as well so

Ba+2 + CO3-2 = BaCO3(s)

Pb+2 + CO3-2 = PbCO3(s)

This will not separate both

c)

Na2S = 2Na+ + S-2

this forms precipitate on both sieds

Ba+2 + S-2 = BaS

Pb+2 + S-2 = PbS

then, this will note help us separte

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