C Chegg Study | Guided ScOWLv2 | Online teaching x C cvg.cengagenow.com/1rn/take
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C Chegg Study | Guided ScOWLv2 | Online teaching x C cvg.cengagenow.com/1rn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining:2:04:42 UNIT TEST Use the References to access important values if needed for this question. 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt A sample of neon gas occupies a volume of 6.65 L at 42.0°C and 0.400 atm. If it is desired to increase the volume of the gas sample to 9.18 L, while decreasing its pressure to 0.245 atm, the temperature of the gas sample at the new volume and pressure must be Question 3 Question 4 Question 5 Question 6 Question 7 Question 8 Question 9 Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Progress: Submit Answer Try Another Version 1 item attempt remaining 0/25 items Due Nov 2 atExplanation / Answer
we have:
P1 = 0.400 atm
P2 = 0.245 atm
V1 = 6.65 L
V2 = 9.18 L
T1 = 42.0 oC
= (42.0+273) K
= 315 K
we have below equation to be used:
(P1*V1)/(T1) = (P2*V2)/(T2)
(0.4 atm*6.65 L)/(315.0 K) = (0.245 atm*9.18 L)/(T2)
T2 = 266 K
T2 = (266-273) oC
= -7.00 oC
Answer: -7.00 oC
Feel free to comment below if you have any doubts or if this answer do not work
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