d. 33 the following balasider the reaction of iron(ll) bromide with sulfturicaci

Question

d. 33 the following balasider the reaction of iron(ll) bromide with sulfturicacid as the following balanc For questions 8 and h sulfuric acid as shown in mical reaction 2 FeBr3 + 3H2S04 Fe2(SO4)3 + 6HBr 8) When an excess o n bromide reacts completely with 4 moles of sulfuricacid howm moles of hydroge omide will be formed? a. 16 b. 12 C. d. 4 If this reaction described in the previous question runs to completion with a species will be present in the reaction vessel? 91 a. Fe2(S04)3 & HBr b. FeBr3, Fe2(SO4)3, & HBr c. H2S04, Fe2(S04)3, & HBr d. FeBr3, H2S04, Fe2(S04)3, & HBr

Explanation / Answer

From the data, Ferric (III) bromide is in excess, so the limiting reagent will be sulfuric acid.

From the equation, 3 moles of sulfuric acid produces 6 moles of hydrogen bromide.

So, calculate the moles of hydrogen bromide, using the 4 moles of sulfuric acid.

4 mol H2SO4 *(6 mol HBr/ 3 mol H2SO4) = 8 moles HBr

Hence, the correct answer is option c.

As per chegg rule, first question is answered.

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