2. (5 points) A mixture of 20.0 grams of sulfur hexafluoride (SF; molar mass 146

Question

2. (5 points) A mixture of 20.0 grams of sulfur hexafluoride (SF; molar mass 146.1g.mol) and 12.0g of carbon 44.01 g.mo) occupies a volume of 9.10 L at T #200C, what is the partial pressure of dioxide (coa molar mass SFo in this mixture? 3. (10 points) Sulfur dioxide, an important intermediate in the synthesis of sulfuric acid, is produced industrially by roasting mineral sulfides, like iron (IlI) sulfide 2 Fe,sds) + 902(g) - 2 Fe2 2 Fe,01s) +6 so, (g) Molar mass (Rmol207.9 64.01 Suppose this reaction is performed in 75.0 liter sealed tank that initially contains 50.0g of Fe S, and an excess of O The reaction is maintained at a temperature of 165 C. Calculate the partial pressure (in torr) of SO in the tank once the reaction is complete.

Explanation / Answer

Q2

a)

mol of SF6 = mass/MW = 20/146.1 = 0.13689

mol of C = masS/MW = 12/44 = 0.27272

total mol = 0.27272+0.13689 = 0.40961

PV = nRT

P = nRT/V= (0.40961)(0.082)(200+273)/(9.10) = 1.74583 atm

now..

x-SF6= mol of SF6/Total mol = 0.13689/0.40961 = 0.33419

P-SF6 = x-SF6 * Ptotal = 0.33419*1.74583 = 0.5834 atm

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