) The e (unbalanced) net ionic equation for the titration reaction is Using the
ID: 551726 • Letter: #
Question
) The e (unbalanced) net ionic equation for the titration reaction is Using the half reactions below.balance the equation. (9 pts) · b) What are the spectator ions in mixture formed when the standard solution is added to the sample solution? (2 pts) 2- k Potassium (c) Fill in the table with the oxidation number of each kind of atom before and after the reaction. 9 pts) Mnou Mn (d) 52.98 mL of 0:100 M KMn04 standard solution is required to reach the endpoint in the titration of a5.00 g sample of iron ore. What is the percent composition by mass of iron in the oniginal ore sample? (6 pts) (52.cem)(a100M)coon () (5.845 (e) If the sample solution started with a volume of 100 mL, what is the concentration of Mn2 ions in the mixture of standard plus sample solution after the endpoint is reached? (6 pts) E2BExplanation / Answer
Iron reacts with permanganate in 5:1 ratio
So volume of KMnO4 in 100ml= 100/6= 16.67mL
Total millimoles of KMnO4= (52.98+16.67)*0.1= 6.968millimoles
Millimoles of KMnO4= Millimoles of Mn+2
Now, Concentration of Mn+2 = 6.968/100+52.98=0.045M
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