9. Calculate the frequency of violet light emitted by a hydrogen atom with a wav

Question

9. Calculate the frequency of violet light emitted by a hydrogen atom with a wavelength of 410.1 nm. a. 9.894 Hz b. 5.433* 1014 c. 1.485* 1014 d. 7.315 104 Hz c. 4.228*10's 10. Give the condensed ground state electron configuration for the expected ion of fluorine a. [He]2s 2p b. [He]2s 2ps c. (He]1s 2s 2p d. [He]2s 2p e. [He]2s'2p 11. Choose the statement that is TRUE. a. Outer electrons efficiently shield one another from nuclear charge. b. Core electrons efficiently shield outer electrons from nuclear charge. c. Valence electrons are most difficult of all electrons to remove. d. Core electrons are the easiest of all electrons to remove. e. All of the above are true. 12. Place the following elements in order of increasing difficulty of removing one electron Li, Ne, Xe a. Ne XecLi e. XecLi

Explanation / Answer

9)

wavelength = 410.1 nm = 4.101*10^-7 m

we have below equation to be used:

frequency = speed of light/wavelength

=(3.0*10^8 m/s)/(4.101*10^-7 m)

= 7.315*10^14 Hz

Answer: d

10)

Number of electron in F = 9

Since charge on F is -1

So, we need to add 1 electrons more

Number of electrons to be arranged = 10

Electronic configuration is 1s2 2s2 2p6

which is same as [He] 2s2 2p6

Answer: d

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