..ooo Sprint 23% 9:18 PM ecourses.pvamu.edu acetic acid, tor example, by using a
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..ooo Sprint 23% 9:18 PM ecourses.pvamu.edu acetic acid, tor example, by using a solid drying agent that is insoluble in the reaction mixture. Describe how the removal of a small quantity of water affects the equilibrium. As water is removed, the reverse reaction is slowed and the forward, water- forming reaction is stimulated. Not all of the water that is removed can be replaced, however, because a new equilibrium could not tolerate a constant concentration of H,O at the same time that the other three concentrations change. Thus, in the new equilibrium the amount of water is somewhat less than in the original equilibrium, the amount of octyl acetate is greater, and the amounts of both 1-octanol and acetic acid are less. Now you try it What should be the effect of (a) adding H,(g)b)removing N(g), and (c) removing NHAs) on a constant-volume equilibrium mixture of N.H2, and NH,? The reaction is N2(g) + 3H2(g)- 2 NH3(g) Deseribe the possible changes that might occur if an aqueous solution of acetic acid is added to an equilibrium mixture for the reaction in previous Predict reaction direction An equilibrium mixture of SO-g), O(g), and SO,(g) is transferred from a 1.00-L flask to a 2.00-L flask. In which direction does a net reaction procced to restore equilibrium? The balanced equation for the reaction is 2503(g) 2 SO2(g) + O2(g)Explanation / Answer
For ammonia:
a)
addition of H2, a reactant, will favour towards the RIGHT side, since the system must counterbalance this addition
it will react N2 + H2 to form NH3
b)
removal of N2, a reactant, will counterbalance from NH3 towards N2 procution
i.e. the LEFT side
therefore, expec NH3 to form N2 and H2
c)
removal of NH3 will favour even more NH3 production, so N2 and H2 react, and decrease in concentration to produce NH3
Q2.
For SO2 production
if V increases, then
[SO3] , SO2, O2 decreases
Q effect
Q = [SO2]^2 * [O2] / [SO3]^2
note that
Q = (1/V)^2 * 1/V /(1/V)^2
Q = 1/V
if V increased, then Q decreases
meaning that the counter balance goes from product towards reactants
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