what is answer part A ,b C,D? « previous | 11 of 19 next » The Ideal Gas Law Par

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what is answer part A ,b C,D?

« previous | 11 of 19 next » The Ideal Gas Law Part A A balloon is floating around outside your window. The temperature outside is-16.2 °C , and the air pressure is 1.34 atm. Your neighbor, who released the balloon, tells you that he filled it with 1.75 moles of gas. What is the volume of gas inside this balloon? Learning Goal To apply the ideal gas law to problems involving temperature, pressure, volume, and moles of a gas Express your answer numerically in liters The four properties of gases (pressure P, volume V, temperature T, and moles of gas n) are related by a single expression known as the ideal gas law: Hints PV = nRT The variable R is known as the universal gas consta R = 0.0820575 L atm/ (mole-K). The units of R dictate the units for all other quantities, so when using this value of R, use units of atmospheres for pressure, liters for volume, and kelvins for temperature nt and has the value Vballoon Submit My Answers Give Up Part B A 16.8 L gas cylinder is filled with 4.20 moles of gas. The tank is stored at 19.6 °C. What is the pressure in the tank? Express the pressure numerically in atmospheres Hints Rank = atm Submit My Answers Give Up

Explanation / Answer

A)

we have:

P = 1.34 atm

n = 1.75 mol

T = -16.2 oC

= (-16.2+273) K

= 256.8 K

we have below equation to be used:

P * V = n*R*T

1.34 atm * V = 1.75 mol* 0.0821 atm.L/mol.K * 256.8 K

V = 27.5 L

Answer: 27.5 L

B)

we have:

V = 16.8 L

n = 4.20 mol

T = 19.6 oC

= (19.6+273) K

= 292.6 K

we have below equation to be used:

P * V = n*R*T

P * 16.8 L = 4.2 mol* 0.0821 atm.L/mol.K * 292.6 K

P = 6.01 atm

Answer: 6.01 atm

C)

we have:

P = 0.9 atm

V = 292.0 L

T = 459.0 oC

= (459.0+273) K

= 732 K

find number of moles using:

P * V = n*R*T

0.9 atm * 292 L = n * 0.08206 atm.L/mol.K * 732 K

n = 4.373 mol

Answer: 4.373 mol

D)

we have:

P = 2.556 atm

V = 24.42 L

n = 2.530 mol

we have below equation to be used:

P * V = n*R*T

2.556 atm * 24.42 L = 2.53 mol* 0.0821 atm.L/mol.K * T

T = 300.5 K

T = 300.5 - 273.1 oC

T = 27.4 oC

Answer: 27.4 oC

Feel free to comment below if you have any doubts or if this answer do not work

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