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Suppose the interference value (I) between loci A and B is the same as the inter

ID: 55087 • Letter: S

Question

Suppose the interference value (I) between loci A and B is the same as the interference between loci B and C, and the order of the loci on the same autosome is A-B-C. If I = 0.05, then a recombination between loci A and B implies:
A. the recombination fraction between A and B is equal to the recombination fraction between B and C.
B. a recombination between loci B and C has an apporixmately 5% probability
C. a recombination between loci B and C has a near 100% possibility
D. a recombination between loci B and C has an approximately 50% probability
E. a recombination between loci B and C has a near 0% probability

Trying to understand this topic. Unfortunately cannot find good resources on the concept but lot of math is shown every where. Know the calculation of how ot find interference and Coefficient of Recombination. Based on the fact intereference is 0.05 (very close to 0), I believe A is the answer meaning

the recombination fraction between A and B is equal to the recombination fraction between B and C.

This is because both A & B as well as B&C have the same I values which is very low. This means each will not interfere with the other's recombination. Hence, the expected recombination fractions should be same which is used in determining the coefficient of recombination.

Explanation / Answer

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