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Question

File EditView History Bookmarks People Window Help urse Home Mast https://session.masteringchemistry.com/myc t itemView?assignmentProblem!D«B7629617&offset;=next HM Exercise 7.56- Enhanced- with Feedback Exercise 7.56 Enhanced- with Feedback Part A An electron traveling at 6.1×105 m/s has an uncertainty in its velocity of 3.03*105 m/s | What is the uncertainty in its position? Express your answer with the appropriate units. You may want to reference(L pages 312-317) Section 7.4 while completing this problem. (+ 10n l ValueUnits Submit My Answers Give Ue Incorrect; One attempt remaining;: Try Again Heisenberg's uncertainty principle states that the product of the uncertaintie greater than or equal to h/4x

Explanation / Answer

use Heisenberg uncertainty principle,

deltax*deltav >= h/(4*pi*m)

Here:

deltav = 3.03*10^5 m/s

mass, m = 9.11*10^-31 Kg

Putting values,

deltax*(3.03*10^5) >= (6.626*10^-34)/(4*3.14*9.11*10^-31)

deltax*(3.03*10^5) >= 5.791*10^-5

deltax > 1.91*10^-10 m

Answer: 1.91*10^-10 m

Feel free to comment below if you have any doubts or if this answer do not work

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