4.(20pts) 1) 10pts) In each pair choose the molecule which has the higher molar

Question

4.(20pts) 1) 10pts) In each pair choose the molecule which has the higher molar entropy under the same conditions. Assume that conditions are such that all molecules are gases (a) (b) (c) (d) N,05 (1 atm, I mole, T-40.0 , NO:0 atm, I mole, T= 400"C) BrCl(g, l mole, l atm, T-25, BrCl(g, l mole, l atm, T245 CO(s, 1 mole, T, 1 atm) CO(1, 1 mole, T, 1 atm) F(g, 1 mole, T, 1 atm) , Fo(g, 1 mole, T, 1 atm) (e) Ar(g, 1 mole, 1 atm, T), Xe(g, 1 mole, I atm, T) (i) 10pts Without doing any calculations, arrange the following reactions in increasing values of AS. Justify your answer (a) H-(g)+ 0(g)2H 00) (b) K(s) + 0 (g)KO (s (c) NH CI(s)>NH,(g) + HCI(g) (d) N-(g) +3 H (g)> 2 NH,(g) (e) CH(g)+H0)>CO(g)+3 H(g)

Explanation / Answer

1) in first case NO 2 will have higher randomness in comparison to N2O5 . Hence NO2 has more molar entropy b) BrCl at t = 45 degree will have more entropy as with increase in temperature randomness increases . C)CO2 gas will have more entropy as in gaseous state randomness is more d) F atom will have more random ness hence it's entropy is more. E) Ar with smaller molecular weight will have maximum randomness. 2 )

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