13 Question (3 points) Many ionic compounds are water soluble, so, for example,

Question

13 Question (3 points) Many ionic compounds are water soluble, so, for example, we can make solutions of sodium iodide, Nal, and lead(II) nitrate, Pb(NO3)2, by simply dissolving the ionic solids in water. In the process of dissolving, the ions from the ionic solutes (sometimes referred to as salts) are split apart and hydrated (surrounded) by water molecules. a See page 170 We represent the species in the sodium iodide solution as Na (aq) and I(aq), and in the lead(l) nitrate solution as the species Pb2 (aq) and NO3 (aq) 2nd attempt Part 1 (1 pt) Feedback .h1 See Periodic Table See Hint Complete the balanced overall ionic equation for sodium iodide dissolving in water. Nal(s)-> Na+(aq) +1-(aq)

Explanation / Answer

Part 1 and Part 2 have been solved correctly by you.

Coming to part 3 :

Here the precipitate formed will be PbI2 , so its physical state will be solid ( and not liquid) , which will be represented as (s) besides the compound.

So the overall ionic equation will be :

2Na+ (aq) + 2NO3- (aq) + Pb2+ (aq) + 2I- (aq) ---> PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)

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