b. Calculate E in kJ/mol C12H22011 for the combustion reaction of sucrose. Answe
ID: 550091 • Letter: B
Question
b. Calculate E in kJ/mol C12H22011 for the combustion reaction of sucrose. Answer 106. Consider the following changes a. N2 (g)N2(1) b. CO(g) + H2O(g) H2 (g) + CO2 (g) CasP2(s) + 6H20(1) 3Ca(OH)2 (s) + 2PHs(g) c. d. 2CH30H() + 302 (g) 2CO2 (g) + 4H20(1) e. 12(s)12(g) At constant temperature and pressure, in which of these changes is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done? 107. A serving size of six cookies contains 4 g of fat, 20 g of carbohydrates, and 2 g of protein. If walking 1.0 mite consumes 170 kJ of energy, how many miles must you walk to burn off enough calories to eat six cookies? Assume the energy content of fats, carbohydrates, and proteins are 8 kcal/g. 4 kcal/g, and 4 kcal/g, respectively. Answer +
Explanation / Answer
Answer
Work done by system on surrounding
a) N2(g) ------> N2(l)
c) Ca3P2(s) + 6H2O(l) ------> 3Ca(OH)2(s) + 2PH3(g)
e) I2(s) -----> I2(g)
Work done by surrounding on system
d) 2CH3OH(l) + 3O2(g) ------>2CO2(g) + 4H2O(l)
No work done
CO(g) + H2O(g) ------> H2(g) + CO2(g)
Explanation
Work = -Force × Displacement
= - PV
So , if there is a volume change in the reaction there will be work done on the system or work done by system
If Volume is decreasing work is done by the surrounding on the system
If Volume is increasing work is done by system on surrounding
Volume change means Volume change based on gaseous substances
If no of mole of gaseous products is more than the no of mole of gaseous reactants then the volume is increased
If no of mole of gaseous products is less than the no of mole of gaseous reactants then the volume is decresed
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