3. IIse the following tahle and rsn to ancwer the questions Standard Heat of Sub
ID: 548980 • Letter: 3
Question
Explanation / Answer
The combustion of butyric acid is
C3H7COOH(l)+ 5O2(g)----à4CO2(g)+ 4H2O(l)
Standard heat of reaction = sum of standard heat of reaction of products- sum of standard heat of reaction of reactants
=4* standard heat of formation of CO2(g)+ 4* standard heat of formation of H2O(l)- {1* Standard heat of formation of C3H7COOH+ 5* standard heat of formation of O2}=-2183.5
Where ,4,4,1 and 5 are coefficients of CO2, H2O, C3H7COOH and O2 repectively.
4*(-393.5)+4*(-285.85)- {1*(standard heat of formation of butyric acid)= -2183.5
Standard heat of formation of butyric acid = 4*(-393.5)+ 4*(-285.85)+2183.5 =-532.5 Kj/mole
2. formation of butyric acid from its elements is 4C(s) + 4H2(g) + O2(g) ---->C3H7COOH(l)
3.
The combustion of butyric acid is
C3H7COOH(l)+ 5O2(g)----à4CO2(g)+ 4H2O(l)
Standard entropy of reaction = sum of standard entropy of products- sum of standard entropy of reactants
=4* standard heat of formation of CO2(g)+ 4* standard heat of formation of H2O(l)- {1* Standard entropy of formation of C3H7COOH+ 5* standard entropy of formation of O2}=-2183.5
Where ,4,4,1 and 5 are coefficients of CO2, H2O, C3H7COOH and O2 repectively.
4*(213.6)+4*(69.96)- {1*(standard entropy of formation of butyric acid+5* 205} =-117.1
Standard entropy of formation of butyric acid+5*205 = 4*(213.6)+ 4*(69.96)+117.1
Standard entropy of formation iof butyric acid =226.34 J/K
3. deltaGf =deltaHo-T*deltaSo= -2183.5-298*(-117.1)/1000= -2148.6 Kj/mole
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