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For the following questions assume that you are starting with 0.50g of copper a.

ID: 548579 • Letter: F

Question

For the following questions assume that you are starting with 0.50g of copper a. Dehydration of Cu(OH)2 If Cu(OH)2 is heated to dryness, how many grams of pure copper oxide should be produced? b. Reaction of CuO with sulfuric acid How many mL of 6.0 M H2SO4 are needed to react completely with to CuO? c. Formation of Cu(s) How many grams of zinc are needed to yield 100% of the starting copper? For the following questions assume that you are starting with 0.50g of copper a. Dehydration of Cu(OH)2 If Cu(OH)2 is heated to dryness, how many grams of pure copper oxide should be produced? b. Reaction of CuO with sulfuric acid How many mL of 6.0 M H2SO4 are needed to react completely with to CuO? c. Formation of Cu(s) How many grams of zinc are needed to yield 100% of the starting copper? For the following questions assume that you are starting with 0.50g of copper a. Dehydration of Cu(OH)2 If Cu(OH)2 is heated to dryness, how many grams of pure copper oxide should be produced? b. Reaction of CuO with sulfuric acid How many mL of 6.0 M H2SO4 are needed to react completely with to CuO? c. Formation of Cu(s) How many grams of zinc are needed to yield 100% of the starting copper? For the following questions assume that you are starting with 0.50g of copper a. Dehydration of Cu(OH)2 If Cu(OH)2 is heated to dryness, how many grams of pure copper oxide should be produced? b. Reaction of CuO with sulfuric acid How many mL of 6.0 M H2SO4 are needed to react completely with to CuO? c. Formation of Cu(s) How many grams of zinc are needed to yield 100% of the starting copper?

Explanation / Answer

a. Cu(OH)2(S) -----> CuO(s) + H2O(g)

No of mol of Cu(OH)2 = 0.5/97.561 = 0.00512 mol

mass of CuO produced = 0.00512*79.545 = 0.4073 grams

b. CuO(s) + H2SO4(aq) ----> CuSO4 + H2O(g)

No of mol of CuO = 0.00512 MOL

nO OF MOL OF h2so4 = 0.00512 mol

volume of H2SO4 = 0.00512/6 = 8.53*10^-4 L

       = 0.853 ml

c. Cu^2+ + Zn ----> Cu(s) + Zn^2+(aq)

No of mol of Cu^2+ = 0.00512 mol

mass of Zn = 0.00512*65.38 = 0.334 grams

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