hemighry.com/myct/ieewosetnetassignmer Core Chemistry Sk Using the Gas Law Reuin
ID: 548578 • Letter: H
Question
hemighry.com/myct/ieewosetnetassignmer Core Chemistry Sk Using the Gas Law Reuing Temperatune and Volume 5544521 re Chemistry Skill Using the Gas Law Relating perature and Volume A sample of gas in a balloon has an iniial empear of 25 C and a voue of 1170Lthe emperature changes to 53C and thare is na change of pressure or ouneo gas what is he new volume,½ ofthe gm? slaw stales that the volume of a gas is directly related to the so te to..ature when-isn0 change inte pressure or amount gas CloureD Express your answer with the appropriate units - My Answers Part B Express your answer wih the appropiahe units ISntsExplanation / Answer
Answer:
Part-A:
Intial Temperature (T1) = 25 C = 25+273 = 298 K
Final Temperature (T2) = 93 C = 93 + 273 = 366 K
Initial Volume (V1) = 1170 L
Final volume (V2) = ?
According to the Charles's law V1 / T1 = V2 / T2
= 1170 / 298 = V2 / 366
(1170 x 366) / 298 = V2
V2 = 1436.979 L
Part-B:
Intial Temperature (T1) = 25 C = 25+273 = 298 K
Final Temperature (T2) = ?
Initial Volume (V1) = 1170 L
Final volume (V2) = 2340 L
According to the Charles's law V1 / T1 = V2 / T2
= 1170 / 298 = 2340 / T2
1170 x T2 = 2340 x 298
T2 = (2340 x 298) / 1170
T2 = 596 K
T2 = 596 -273
T2 = 3230C
Question-7:
Part-A:
Intial Temperature (T1) = 400 K
Final Temperature (T2) = 500 K
Initial Volume (V1) = 46 L
Final volume (V2) = ?
According to the Charles's law V1 / T1 = V2 / T2
= 46 / 400 = V2 / 500
(46 x 500) / 400 = V2
V2 = 57.5 L
Part-A:
Intial Temperature (T1) = 26 C = 26+273 = 299 K
Final Temperature (T2) = 77 C = 77 + 273 = 350 K
Initial Volume (P1) = 245 Torr
Final volume (P2) = ?
According to the Gas law P1 / T1 = P2 / T2
= 245 / 299 = P2 / 350
(245 x 350) / 299 = P2
P2 = 286.789 Torr
Part-B:
Intial Temperature (T1) = 26 C = 26+273 = 299 K
Final Temperature (T2) = ?
Initial Volume (P1) = 245 Torr
Final volume (P2) = 2454 Torr
According to the Gas law P1 / T1 = P2 / T2
= 245 / 299 = 2454 / T2
(245 x T2) = 2454 x 299
T2 = 2994.88 K
T2 = 2994.88 - 273
T2 = 2721.880C
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