1WKU Transfer Credit Infon! GEListsummer.pdf f GR rn Kentucky Uni × j.com/ibiscm

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1WKU Transfer Credit Infon! GEListsummer.pdf f GR rn Kentucky Uni × j.com/ibiscms/mod/ibis/view.php?id-3983993 10/27/2017 12.00 AM em Print 643/10010/23/2017 03:43 PM Calculator Periodic Table uestion 6 of 7 Sapling Learning The generic metal A forms an insoluble salt AB(s) and a complex ACslaq). The equilibrium concentrations in a solution of and [ACsl 0.100 M. Determine the formation constant, K, of ACs AC were foundto be [A] 0.100 M, [CI-o0290 M Number K, = 114.8 107 The solubility of AB(s) in a 1.000-M solution of C(aq) is found to be 0.156 M What is the Kp of AB? Number K = 3.25x10 There is a hint available! Vew the hint by bollom drvider bar on the on the divider bar again to hide the hint Giose Previous Gve Up & Vew So ation Q) Chek Answer w Next

Explanation / Answer

[Kf] = [AC5] / [A][C]^5

Kf = 0.100 / (0.100) (0.0290)^5

Kf = 0.100 / 2.05*10^-9

Kf = 48780487.8

AB(s) + 5C(aq)  <-> AC5(aq) + B(aq)

the change is equivalent to the solubility,therefore it is 0.156M

then set up the K

[AC5] = 0.156

[B] = 0.156

[C] = 1.000-5(0.156)

K = [0.156] [0.156] / [ 1.00-5(0.156)]^5

K = 0.024336 / 0.0005153632

K = 4.722106

noe didvide by Kf

4.722106 / 48780487.8

Kof AB = 9.68*10^-8

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