SECTION 1: EACH QUESTION CARRIES 5 POINTS, UNLESS SPECIFIED! 1. An oxygen cylind
ID: 547249 • Letter: S
Question
SECTION 1: EACH QUESTION CARRIES 5 POINTS, UNLESS SPECIFIED! 1. An oxygen cylinder used in a hospital contains 35.40 dms of oxygen gas at a pressure of 149.6 atm. What volum a pressure of 1.00 atm f the temperature remaips constant? e would the oxygen occupy if it were transferred to a container that maintained PViY:Vz 529 5.9 dm3 2. If 1.00 mol of an ideal gas at STP were confined to a cube, what would be the length in dm of the edge of this cube? cw 3. If 5.76 g of AgO is heated and the O2 gas produced by the reaction is collected in an evacuated flask, what is the pressure of the O2 gas if the volume of the flask is 0.65 dm2 and the gas temperature is 25 C A. 4. A chemist is investigating the conversion of atmospheric nitrogen to usable form by the bacteria that inhabit the root systems of certain legumes. What is the pressure in kPa exerted by 1.25 g of nitrogen gas in a flask of volume 250 cm3 at 20 5. Calculate the final pressure of. a gas that is com- pressed from a volume of 20.0 dm2 to 10.0 dm and cooled from 100 °C to 25 -cjr the intujl pressure is 1,.00 bar 6. The mole fraction of NHs in a sample of 10.0 mol of gas is 0.285. What mass of NHs is present in the sample? 15Explanation / Answer
Q2
if 1 mol of gas occupies = 22.4 L
then
if it were a cube --> V = l^3
l = (V)^(1/3) = (22.4*10^3)^(1/3) = 28.1891 cm3
Q3
mol of Ag2O = mass/MW = 5.76 /231.73580 = 0.02485 mol of Ag2O
mol of O2 = 1/2*Ag2O = 1/2*0.02485 = 0.012425 mol of O2
now..
PV = nRT
P = nRT/V= (0.012425)(0.082)(25+273)/(0.65) =
P = 0.4671 atm = 0.4671*101325 Pa = 47328.9 Pa
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