1. Which of the following accurately portrays the relationship of pressure and v

Question

1. Which of the following accurately portrays the relationship of pressure and volume in Boyle's Law? A) Air in the lungs of a scuba diver compresses at greater depths B) A tire with low air pressure is filled with more air at room temperature C) A balloon shrinks at lower temperatures D) A gas cylinder can be filled with more gas if it is cooled E) none of the above portray Boyle's Law At zero degrees Celsius, a sample of helium gas occupies a volume of 89.6 L at 760 mm Hg. What is the mass in grams of this sample? 2. A) 16.0 g B) 7.19 g C) 1.80 g D) 4.00 g E) 1.30 g 3. 1.00 mol of an ideal gas occupies a volume of 22.4 liters at 273.15K. What volume does this gas occupy at room temperature (assume 25.0 deg Celsius) A) 20.5 L B) 2.05 L C) 22.4 L D) 24.5 L E) 1.88 L 4. Which of the following applies or is directly related to the Kinetic Molecular Theory of gases A) Volatile perfume molecules have a scattered, indirect path when moving across a room B) Steam condensates at lower temperatures on glass windows C) Carbon dioxide has significant dipole-dipole interactions at higher pressures D) Hydrogen Fluoride gas reacts violently in the air with moisture E) none of the above A 0.855 g sample of gas occupies a volume of 302 milliliters at 400 K and a pressure of 965 mm Hg. What is the molar mass of this gas? 5. d = PM/RT where M = molar mass (g/mol) A) 2.44 g/mol B) 11.7 g/mol C) 7.32 g/mol D) 73.2 g/mol E) 1.17 g/mol

Explanation / Answer

1)

Boyle’s law is relation between P and V. This is portrayed by A

In B,C,D. temperature appears which is not a variable in Boyle’s law.

Answer: A

2)

we have:

P = 760.0 mm Hg

= (760.0/760) atm

= 1 atm

V = 89.6 L

T = 0.0 oC

= (0.0+273) K

= 273 K

find number of moles using:

P * V = n*R*T

1 atm * 89.6 L = n * 0.08206 atm.L/mol.K * 273 K

n = 3.998 mol

Molar mass of He = 4.003 g/mol

mass of He,

m = number of mol * molar mass

= 3.998 mol * 4.003 g/mol

= 16.0 g

Answer: A

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