periment 8: Preparation of Adipie Acid from Cyclohesene (2 pts) (1 pts) 1 pts) (

Question

periment 8: Preparation of Adipie Acid from Cyclohesene (2 pts) (1 pts) 1 pts) (2 pts) 3 pts) 4 pts) 1. Turned in on time 2. Header for all pages 3. Format 4. Main Idea S. Reactions) 6. Tab 7. Pre-lab Questions le of physical (4 pts ) PRELAB QUESTIONS: 1. W at is the structure and IUPAC name for adipic acid? O1H 2. Balance the reaction below and calculate the theoretical yield. Stat with I gram of 3 ene and an gxcess of KMnO KMno4 +MnO warm, cone. The product of this reaction is a carboxylic acid. What reaction can be done to make this product more soluble in water? 3.

Explanation / Answer

1.

HOOC-CH2-CH2-CH2-CH2-COOH

Hexane-1,6-dioicacid

2.

CH3CH2CH=CHCH2CH3 + KMnO4 -----------> 2 CH3CH2COOH + MnO2

Mass of 3-hexene = 1 g.

Molar mass of 3-hexene = 84 g/mol

Moles of 3-hexene = 1 / 84 = 0.0119 mol

From the balanced equation,

1 mol of 3 - hexene forms 2 mol of propanoicacid

Then, 0.0119 mol of 3-Hexene forms 0.0238 mol of propanoic acid.

Theoretical yield of propanoic acid = moles * molar mass = 0.0238 * 74 = 1.76 g. of propanoic acid

3.

Potassium salt of carboxylic acid can be formed.

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