a.Wastewater from a winery contains approximately 1.8 g/L glucose (C6H12O6), 1.8

Question

a.Wastewater from a winery contains approximately 1.8 g/L glucose (C6H12O6),
1.8 g/L fructose (C6H12O6) and 250 mg/L acetic acid (CH3COOH). What would
be the BOD5 and ultimate BOD assuming the first order rate constant is 0.23
d-1 (base e)?

b.Determine the number of completely mixed chlorine contact chambers each
having a detention time of 30 min that would be required in a series
arrangement to reduce the bacterial count of a treated effluent from 10^6 to14.5 organisms/mL .if the first order removal rate constant is equal to 6.1 h-1.
If a plug flow chlorine contact chamber were used with the same detention
time as the series of completely mixed chambers, what would the bacterial
count be after treatment?

Explanation / Answer

BOD mg/l = (Initial DO - DO5) x Dilution Factor

                        Dilution Factor = Bottle Volume (300 ml)

                                                                Sample Volume

temperature is required

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