A 0.170 M Solution Of An Et arning.com/ibiscms/mod/ibis/view.phpid 43654 Gradebo
ID: 545898 • Letter: A
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A 0.170 M Solution Of An Et arning.com/ibiscms/mod/ibis/view.phpid 43654 Gradebook O 10/22/2017 1155 PM O 34/5010/201201703:47 PM Print Caluator Periodic Table Question 24 of 50 presented by Sapling Leaming D has an observed rotation of +0.14 in a A 0.170 M solution of an enantiomerically pure chiral 1-dm sample container. The molar mass of the is 116.0 glmol. b) What is the observed rotation if this solution is mixed with an equal volume of a solution that is 0.170 M in L, the enantiomer of D? (a) What is the specific rotation of D Number deg mL Number gdm deg (c) What is the observed rotation if the solution of D is diluted with an equal volume of solvent? (d) What is the specific rotation of D after the dilution described in part (c)? Number deg mL deg g- dm What is the observed rotation of 100 mL of a solution that contains 0.01 mole of D and 0.005 mole of L? (Assume a 1-dm path length.) e) What is the specific rotation of L the enantiomer of after the dilution described in part (c)? deg mL g dm deg Prevous Grve Up & View Souton eCheck Answer ONet aExt about us careers privacy policy terms of use cont.Explanation / Answer
a)
concentration = 0.170 x 116 = 19.72 g / L = 0.01972 g/mL
observed rotation = + 0.14 o
specific rotation = observed rotation / l x concnetration
= 0.14 / 1 x 0.01972
specific rotation = 7.10 deg .mL / g.dm
b)
equial volume and equal concnetrations of solutions mixed , racemic mixure formed.
observed rotation = 0 deg
c)
volume doubled , then concentration is halved.
c = 0.01972 / 2 = 0.00986
observed rotation = 7.10 x 0.00986 x 1
observed rotation = 0.070 deg
d)
specific rotation is uneffected by dilution
specific rotation = 7.1
e)
specific rotation of L = - 7.10
f)
moles= 0.01 - 0.005 = 0.005
concentration = 0.005 / 0.1 = 0.05 M
= 0.05 x 116 / 1000
= 0.0058
observed rotation = 0.0058 x 7.10 x 1
observed rotation = 0.041
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