A sample consists of one or more of the following salts: Cu(CH3CO2)2 (acetate),

Question

A sample consists of one or more of the following salts: Cu(CH3CO2)2 (acetate), BaCl2, (NH4)2SO4, SrCO3, KNO3. The sample, when treated with water, gives a white precipitate that is filtered off and a blue solution. The precipitate is a white solid that is completely insoluble, both in water and in 6M HCl solution. Which compounds MUST be present? Explain why. Which compounds MUST be absent? Explain why. Which compounds are INDETERMINATE - unable to determine if present or absent. I'm confused about what happens to ammonium sulfate

Explanation / Answer

  (NH4)2SO4 and BaCl2 combined form a precipitate when Ba (2+) reacts with SO4 (2-).

BaSO4 forms a white precipitate in this equation because we can assume double-replacement activity between the compounds as follows:

(NH4)2SO4 + BaCl2 ---------> NH4Cl(aq) + BaSO4(s) (WHITE PRECIPITATION)

Ammonium Chloride is soluble (not precipitate) and Barium Sulfate is insoluble (precipitate)

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