Do Questions from 1-5. SHOW YOUR WORK VERY, VERY CLEARLY 1. A mixture of 3.5 g o
ID: 545107 • Letter: D
Question
Do Questions from 1-5.
SHOW YOUR WORK VERY, VERY CLEARLY 1. A mixture of 3.5 g of hydrogen and 26.0 g of oxygen is made to react to form water a) Which reactant is limiting? b) Which reactant will be left over? c) How many grams of the reactant will be left over? produced? d) How many grams of water will be 2. A large neon sign is to be filled with a mixture of gases, including 6.348 g of neon. What number of mole is this? 3. A metal, M, forms an oxide having the simplest formula M20. This oxide contains 52.9 % of metal by mass. a) Calculate the atomic weight of the metal; b) Identify the metal. 4. From a 45.0 g sample of an iron ore containing Fe,O, 1.5 g Fe is obtained by the 3Fe + 2C02, what is the percent if Feo.? following reaction: Fe,04 + 2C Balance the following Equations: a) ZnCl2+ NaOH c) Al + HCl AIC, + H2 5. Zn(OH)2 + Naci d) CsHu + O2 CO2 + H2OExplanation / Answer
1)
a)
Molar mass of H2 = 2.016 g/mol
mass(H2)= 3.5 g
number of mol of H2,
n = mass of H2/molar mass of H2
=(3.5 g)/(2.016 g/mol)
= 1.736 mol
Molar mass of O2 = 32 g/mol
mass(O2)= 26.0 g
number of mol of O2,
n = mass of O2/molar mass of O2
=(26.0 g)/(32 g/mol)
= 0.8125 mol
Balanced chemical equation is:
2 H2 + O2 ---> 2 H2O +
2 mol of H2 reacts with 1 mol of O2
for 1.7361 mol of H2, 0.8681 mol of O2 is required
But we have 0.8125 mol of O2
so, O2 is limiting reagent
Answer: oxygen is limiting
b)
Answer: Hydrogen is in excess
c)
According to balanced equation
mol of H2 reacted = (2/1)* moles of O2
= (2/1)*0.8125
= 1.625 mol
mol of H2 remaining = mol initially present - mol reacted
mol of H2 remaining = 1.7361 - 1.625
mol of H2 remaining = 0.1111 mol
Molar mass of H2 = 2.016 g/mol
mass of H2,
m = number of mol * molar mass
= 0.1111 mol * 2.016 g/mol
= 0.224 g
Answer: 0.224 g
d)
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
According to balanced equation
mol of H2O formed = (2/1)* moles of O2
= (2/1)*0.8125
= 1.625 mol
mass of H2O = number of mol * molar mass
= 1.625*18.02
= 29.3 g
Answer: 29.3 g
I am allowed to answer only 1 question at a time
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.