argk of proudion chie ww decorspcoed ascordäing to the frllowing equ lew mony mo

Question

argk of proudion chie ww decorspcoed ascordäing to the frllowing equ lew mony moles of eoygen are feed B) 0.0580 mal C) 0.0387 mel 0.0820 mel E) nose of the 22 Phphnic aid ess be prepared by reactions of salfick acit with "psphale odk" econling to the eqution Suppose the reaction is oarsiod our varting with 12ofCa suhstance is the liemiting reacan and 97.4 g of Hso. Waich B) H:so E) sone of thess 23. A 5.95-g sarple of AgNO, is reciad with BaCl, according to he oyeation ZAgNC-la). Ba,Esv) 2Ag@() + Ba No,hlaq) lo geive 3,17E of Agcl Whatis the pencest yicld of Ascn B) 53.3% D) 63.1% E) 100% 24. Giveo te cquatiet) 3A + 8%c-D, you rent relex cEA with i moleof8, which offe following is troe? A) A is the imsting reaktax because of is ligher molar mass B) A is the limiting reactank becauoe you nood 3 moles of 4 and have 2 C) & is the lirmiting rectane because you have fewer moles of & tdha D) & is the limiting reosctank because 3 A molecules react with 1 & molectlc E) Neithar reactont is lirniting 25. Caleulate the mobe miss of bariun sulSte A) 233.40 gnol B) 201.40 gmol C) 354.73 go D) 514.R7gmol 5) 21340gmol

Explanation / Answer

21)

Molar mass of KClO3 is 122.55 g/mol

Number of moles of KClO3

7.11 g KClO3 × ( 1 mol KClO3 / 122.55 g KClO3)

= 0.0580 mol KClO3

From the balanced equation the mole ratio of KClO3 and O2 is

(2 mol KClO3 / 3 mol O2) or

( 3 mol O2 / 2 mol KClO3)

The number of moles of O2 formed is,

0.0580 mol KClO3 × ( 3 mol O2 / 2 mol KClO3)

= 0.0870 mol O2

Hence the correct option is (D) 0.0870 mol.

24)

Finding the limiting reactant.

Number of moles of A required is

1 mol B × ( 3 mole A / 1 mol B)

= 3 mol A

But the number of moles of A given is 2.

Hence A is limiting reactant.

Hence correct option is

(B).

25)

Molar mass of Barium sulfite BaSO3 is 217.391 g/mol

Hence the correct option is (E). 217.40 g/mol

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