Why is option four the correct answer and how would you solve this problem? Ques

Question

Why is option four the correct answer and how would you solve this problem?

Question 1 0/1 pts The observed reactivity trend in SN1, SN2, E1, and E2 reactions, for a given alkyl group, is that alkyl iodides react faster than other alkyl halides. That is because The C-I bond is stronger. red OThe iodide ionI) is a stronger base than other halide ions. The leaving group, the iodide ion (T), is less stable than other halide ions wer The leaving group, the iodide ion (I-), is more stable than other halide ions

Explanation / Answer

The weaker the base, the less tightly it is bonded to the carbon and the easier it is to break the carbon-halogen bond. As a result, an alkyl ioide is the most reactive.

When comparing atoms that are very different in size, the size of the atom is more important than its electronegativity in determining how well it bears its negative charge.

As the halide ion increases in size, its stability increases because its negative charge is spread over a larger volume of space.therefore, iodide ion is the most stable halide ion even though iodine is the least electronegative of the halogens.

Therefore, the fourth option is correct.

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