coefficients, what is the coefficient of 02 molecule? H2O(/) /CO2 (g) + 02(g) Cs
ID: 544751 • Letter: C
Question
coefficients, what is the coefficient of 02 molecule? H2O(/) /CO2 (g) + 02(g) CsHsCH3(1) + A) 9 B) 4 C) 7 D) 12 E) 13 15. In the following reaction, 6.00 kg of CaF2 is treated with an excess of H2SO4, and produces 2.86 kg of HF. Calculate the percent yield of HF CaF2 + H2SO4 CaSO4 +2HF A) 93.0% B) 30.8% C) 66.0% D) 33.0% E) 48.890 16. A metal, M, is converted to the metal sulfate, M2(SO4)3. Then a solution of the metal sulfate was treated with calcium chloride to give calcium sulfate precipitate. If 1.200 g of the metal gave 5.451 g calcium sulfate, what is the identity of metal M?Explanation / Answer
molar mass of CaF2 = 78.1 g/mol
mass of CaF2 = 6.00 kg
= 6000 g
number of mole of CaF2 = (given mass of CaF2)/(molar mass of CaF2)
= 6000/78.1
= 76.8 mol
according to reaction given
1 mole of CaF2 react with 2 mole of HF
76.8 mole of CaF2 react with (2*76.8) mole of HF
number of mole of HF formed = 153.6 mole
molar mass of HF = 20.0 g/mol
mass of HF formed theoretical = (number of mole of HF formed)*(molar mass of HF )
= 153.6*20.0
= 3072 g
= 3.702 kg
%yield = {(actual mass of HF)/(theoretical mass of HF)}*100
= (2.86/3.702)*100
= 77.3%
Answer : 77.3%
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