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i Safari File Edit View History Bookmarks Window Help 90% Thu Oct 19 11:41 AM a saplinglearning.com Student Hu My Gradee Chegg Stud Chegg Stud how to print. Sapling Learning itied folder State University of Denver-CHE 1800 7 Chapter 6-7 Jump to Rachel Westman 0 10/23/2017 12:55 AM 13.915 () 10/17/2017 12:42 PM Gradebook PrintClculator Periodie Tabk Question 10 of 15 MSU DENVER HONO...ON 2017 Map Sapling Learning Given the following reactions, where X represents a generic metal or metalloid, 1,--241.8 kJ H,-+237.9 kJ AH,--92.3 k AH,-677.9 k 8 001.pd HC ,--44.0 kJ what is the enthalpy, H, for this reaction? Number xCI)2H.oll-> xo,ls)+4Hcg) kJ Tacls Previous Give Up & View Solution 9 Check AnswerNext a Exi Hint 19

Explanation / Answer

we need, XCl4(s) in the left side so:

from rxn 2; invert it

XCl4(s) = X(s) + 2Cl2(g) H = -237.9

now, we need XO2 in the left side; from rxn 4,

X(s) + O2(g) = XO2(s) H = -677.9

we need HCl with 4 coefficient, so from rxn3, multiply by 4

2H2(g) + 2Cl2(g) = 4HCl(g) H = 4(-92.3) = -369.2

add rxn

2H2(g) + 2Cl2(g) + X(s) + O2(g) + XCl4(s) = X(s) + 2Cl2(g) + XO2(s) + 4HCl(g)    H = -237.9-677.9 -369.2

cancel common terms

2H2(g) + O2(g) + XCl4(s) = XO2(s) + 4HCl(g)    H = -1285

we need to get rid of H2 and O2, so we need to add rxn 1, invert it and multiply by 2

2H2O(g) = 2H2(g) + O2(g) H = -2*(-241.8) = 483.6

add bth

2H2O(g) + 2H2(g) + O2(g) + XCl4(s) = XO2(s) + 4HCl(g) + 2H2(g) + O2(g) H = -1285+483.6

simplify

2H2O(g) +XCl4(s) = XO2(s) + 4HCl(g) H = -801.4

get rid of H2O(g) via H(l), inver rxn 5

2H2O(l) = 2H2O(g) H= 2*44= 88

add both

2H2O(l) + 2H2O(g) +XCl4(s) = XO2(s) + 4HCl(g) + 2H2O(g) H = -801.4+88

simplify

2H2O(l) + XCl4(s) = XO2(s) + 4HCl(g) H =-713.4

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