Q1-A hot air balloon is filled with 1.51 × 106 L of an ideal gas on a cool morni
ID: 543708 • Letter: Q
Question
Q1-A hot air balloon is filled with 1.51 × 106 L of an ideal gas on a cool morning (11 °C). The air is heated to 121 °C. What is the volume of the air in the balloon after it is heated? Assume that none of the gas escapes from the balloon.
Q2- A sample of an ideal gas at 1.00 atm and a volume of 1.09 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 65.0 atm, what was the volume of the sample? Assume that the temperature was held constant.?
Q3-An ideal gas in a sealed container has an initial volume of 2.70 L. At constant pressure, it is cooled to 21.00 °C where its final volume is 1.75 L. What was the initial temperature?
Q4-A sealed container holding 0.0255 L of an ideal gas at 0.985 atm and 69 °C is placed into a refrigerator and cooled to 45 °C with no change in volume. Calculate the final pressure of the gas.
Q5-If the initial temperature of an ideal gas at 2.250 atm is 62.00 °C, what final temperature would cause the pressure to be reduced to 1.550 atm?
Q6-A sample of an ideal gas has a volume of 2.22 L at 287 K and 1.07 atm. Calculate the pressure when the volume is 1.96 L and the temperature is 306 K.
Q7-A sample of an ideal gas has a volume of 3.60 L at 12.40 °C and 1.70 atm. What is the volume of the gas at 21.20 °C and 0.993 atm?
Explanation / Answer
1)
Given:
Vi = 1.51*10^6 L
Ti = 11.0 oC
= (11.0+273) K
= 284 K
Tf = 121.0 oC
= (121.0+273) K
= 394 K
use:
Vi/Ti = Vf/Tf
1.51*10^6 L / 284.0 K = Vf / 394.0 K
Vf = 2.09*10^6 L
Answer: 2.09*10^6 L
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