if a 40.0g block of copper at 100 degrees C is added to 100g of water at 25.0 de
ID: 542812 • Letter: I
Question
if a 40.0g block of copper at 100 degrees C is added to 100g of water at 25.0 degrees C calculate the final temperature assuming no heat is lost to the surroundings. the specific heat of water is 4.184 J/g degree C. the specific heat of copper is 0.385 J/g degree C if a 40.0g block of copper at 100 degrees C is added to 100g of water at 25.0 degrees C calculate the final temperature assuming no heat is lost to the surroundings. the specific heat of water is 4.184 J/g degree C. the specific heat of copper is 0.385 J/g degree C if a 40.0g block of copper at 100 degrees C is added to 100g of water at 25.0 degrees C calculate the final temperature assuming no heat is lost to the surroundings. the specific heat of water is 4.184 J/g degree C. the specific heat of copper is 0.385 J/g degree CExplanation / Answer
Let us denote Water by symbol 1 and copper by symbol 2
m1 = 100.0 g
T1 = 25.0 oC
C1 = 4.184 J/goC
m2 = 40.0 g
T2 = 100.0 oC
C2 = 0.385 J/goC
T = to be calculated
Let the final temperature be T oC
use:
heat lost by 2 = heat gained by 1
m2*C2*(T2-T) = m1*C1*(T-T1)
40.0*0.385*(100.0-T) = 100.0*4.184*(T-25.0)
15.4*(100.0-T) = 418.4*(T-25.0)
1540 - 15.4*T = 418.4*T - 10460
T= 27.7 oC
Answer: 27.7 oC
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